Car leaves skid mark 92m long. Assuming a deceleration of 7m/s^2 estimate the speed of the car before breakin
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Car leaves skid mark 92m long. Assuming a deceleration of 7m/s^2 estimate the speed of the car before breakin

[From: ] [author: ] [Date: 11-09-14] [Hit: ]
.u = 35.......
Please explain if possible how to get the answer because I'm not sure how to do this problem.

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the skid mark tells you how far the car traveled once braking was initiated

use vf^2=v0^2 + 2ad

vf=final velocity =0
v0=initial velocity which is what we will find
a=accel = -7m/s/s note that it is negative since it is slowing down
d=distance traveled = 92m

0=v0^2-2*7*92

v0=35.9m/s

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v^2 = v0^2 + 2*a*x. where v0 is initial velocity v is final velocity x is distance, a is acceleration.

v = 0 .... car STOPPED.
v0 = what you want to find.
a = -7: DECELERATION.
x = 92 m.

Solving you get v0^2 = 2*7*92.... v0= sqrt(1288). Whatever that is...

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assuming skid mark 92m long= breaking distance s

v=0; a= - 7
v^2 = u^2 + 2as
0 = u^2 - 2 * 7 * 92

u = 35.89m/s
answer
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