Please explain if possible how to get the answer because I'm not sure how to do this problem.
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the skid mark tells you how far the car traveled once braking was initiated
use vf^2=v0^2 + 2ad
vf=final velocity =0
v0=initial velocity which is what we will find
a=accel = -7m/s/s note that it is negative since it is slowing down
d=distance traveled = 92m
0=v0^2-2*7*92
v0=35.9m/s
use vf^2=v0^2 + 2ad
vf=final velocity =0
v0=initial velocity which is what we will find
a=accel = -7m/s/s note that it is negative since it is slowing down
d=distance traveled = 92m
0=v0^2-2*7*92
v0=35.9m/s
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v^2 = v0^2 + 2*a*x. where v0 is initial velocity v is final velocity x is distance, a is acceleration.
v = 0 .... car STOPPED.
v0 = what you want to find.
a = -7: DECELERATION.
x = 92 m.
Solving you get v0^2 = 2*7*92.... v0= sqrt(1288). Whatever that is...
v = 0 .... car STOPPED.
v0 = what you want to find.
a = -7: DECELERATION.
x = 92 m.
Solving you get v0^2 = 2*7*92.... v0= sqrt(1288). Whatever that is...
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assuming skid mark 92m long= breaking distance s
v=0; a= - 7
v^2 = u^2 + 2as
0 = u^2 - 2 * 7 * 92
u = 35.89m/s
answer
v=0; a= - 7
v^2 = u^2 + 2as
0 = u^2 - 2 * 7 * 92
u = 35.89m/s
answer