between temperature extremes of -20°C and 35°C?
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The equation for linear expansion (e) is ..
e = Lo.α.∆θ .. (in m)
α = coef.of linear expansion
Lo = original length in m
∆θ = temperature change in ºC
e = (518)(11.0^-6)(55) .. .. ►e = 0.313 m
e = Lo.α.∆θ .. (in m)
α = coef.of linear expansion
Lo = original length in m
∆θ = temperature change in ºC
e = (518)(11.0^-6)(55) .. .. ►e = 0.313 m
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You need to specify the coefficient of linear expansion to solve this problem.
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dL = Lo*α*dT = 518*11E-6*(35 - (-20)) = .313 m