Prove that if a is an upper bound for A, and if a is also an element of A, then it must be that a = sup A.
Favorites|Homepage
Subscriptions | sitemap
HOME > Mathematics > Prove that if a is an upper bound for A, and if a is also an element of A, then it must be that a = sup A.

Prove that if a is an upper bound for A, and if a is also an element of A, then it must be that a = sup A.

[From: ] [author: ] [Date: 11-09-14] [Hit: ]
Thus, sup(A) = a.......
If a is an upper bound for A, then sup(A) exists, and:

sup(A) <= a

If a is an element of A, then, since sup(A) is an upper bound on A, we have:

a <= sup(A)

Thus, sup(A) = a.
1
keywords: Prove,is,be,then,bound,and,if,upper,element,it,of,also,must,sup,an,that,for,Prove that if a is an upper bound for A, and if a is also an element of A, then it must be that a = sup A.
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .