please solve (sinθ+cosθ)2+(sinθ-cosθ)2=0 i needed it tommorow please help
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(sinθ+cosθ)²+(sinθ-cosθ)²=0
(sin²θ + 2sinθcosθ + cos²θ)+(sin²θ - 2sinθcosθ + cos²θ)=0
(sin²θ+ cos²θ) + 2sinθcosθ - 2sinθcosθ +(sin²θ+ cos²θ)=0
1 + 0 +1=0
2≠0
no solutions
(sin²θ + 2sinθcosθ + cos²θ)+(sin²θ - 2sinθcosθ + cos²θ)=0
(sin²θ+ cos²θ) + 2sinθcosθ - 2sinθcosθ +(sin²θ+ cos²θ)=0
1 + 0 +1=0
2≠0
no solutions
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it depend wether you mean
(sinθ+cosθ)*2+(sinθ-cosθ)*2=0
or
(sinθ+cosθ)^2+(sinθ-cosθ)^2=0?
if it's the first one then the first answer is kind of correct if it's the second one the second answer is correct...
(sinθ+cosθ)*2+(sinθ-cosθ)*2=0
or
(sinθ+cosθ)^2+(sinθ-cosθ)^2=0?
if it's the first one then the first answer is kind of correct if it's the second one the second answer is correct...
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2SINQ+2COSQ+2SINQ-2COSQ=0
2SINQ=0
SINQ=0
Q=(0 AND 180 AND 360 AND...............................)
SEND YOUR THANK'S TO ME IF IT WAS RIGHT.
2SINQ=0
SINQ=0
Q=(0 AND 180 AND 360 AND...............................)
SEND YOUR THANK'S TO ME IF IT WAS RIGHT.