I need to find the lengths A(2,1) B(6,3) and of B(6,3) C(5,5), the method of how itsdone would be very much appreciated.
-
Okay so I'm pretty sure you should know what Pythagoras is. It's basically in a right triangle:
a^2 + b^2 = c^2 where c is the longest side.
So basically this is the formula:
sqrt[(x2 - x1)^2 + (y2 - y1)^2]
Let's apply that right now.
sqrt[(6 - 2)^2 + (3 - 1)^2]
sqrt(4^2 + 2^2)
sqrt(16 + 4)
sqrt(20)
2sqrt(5)
So for the first one, the answer is 2sqrt(5), or 4.472135955
Now for the second:
sqrt[(5 - 6)^2 + (5 - 3)^2]
sqrt[(-1)^2 + 2^2]
sqrt(1 + 4)
sqrt(5)
And that's your second answer: sqrt(5) or 2.236067977
a^2 + b^2 = c^2 where c is the longest side.
So basically this is the formula:
sqrt[(x2 - x1)^2 + (y2 - y1)^2]
Let's apply that right now.
sqrt[(6 - 2)^2 + (3 - 1)^2]
sqrt(4^2 + 2^2)
sqrt(16 + 4)
sqrt(20)
2sqrt(5)
So for the first one, the answer is 2sqrt(5), or 4.472135955
Now for the second:
sqrt[(5 - 6)^2 + (5 - 3)^2]
sqrt[(-1)^2 + 2^2]
sqrt(1 + 4)
sqrt(5)
And that's your second answer: sqrt(5) or 2.236067977
-
Dear use the distance formula for your question:
d= √(x2-x1)^2+(y2-y1)^2
For coordinates A(2,1) B(6,3) the value of d=2(5)^1/2
For coordinates B(6,3) C(5,5) the value of d=(5)^1/2
d= √(x2-x1)^2+(y2-y1)^2
For coordinates A(2,1) B(6,3) the value of d=2(5)^1/2
For coordinates B(6,3) C(5,5) the value of d=(5)^1/2