Physics Integrated Exercise.!

I need some help with this Physics "Integrated Exercise"(IE). [An IE is a two part exercise. The first part typically requires a conceptual answer choice based on physical thinking and basic principles. The following part is quantitative calculations with the conceptual choice made in the first part of the exercise.]

A car is driven 13 mi east and then a certain distance due north, ending up at a position 25 degrees north of east of its initial position. (a) The distance traveled by the car due north is (1) LESS THEN, (2) EQUAL TO, (3) GRATER THAN 13 mi. Why? (b) What distance due north does the car travel?

If anyone can please help me with this problem it would be greatly appreciated.! I am horrible at word problems.

THANKS.

the key to part a is to realize that if the distance north was exactly equal to the distance east, the final position would be at an angle of 45 degrees with respect to the east axis

since the angle is 25 degrees, the north distance must be less than the east

to find the distance numerically, draw a triangle and find

tan(theta)=y/13 where y is the distance north

y = 13 tan 25 = 6.06 mi