Acceleration of an electron with initial and final velocity
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Acceleration of an electron with initial and final velocity

[From: ] [author: ] [Date: 11-09-11] [Hit: ]
(5.05*10^5)^2 = (1.06*10^5)^2 + 2*0.a = 24.37*10^10/(2*0.a = 1.......
An electron with initial velocity v0 = 1.06 × 105 m/s enters a region 1.0 cm long where it is electrically accelerated (Fig. 2-23). It emerges with velocity v = 5.05 × 105 m/s. What is its acceleration, assumed constant?

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Hello

v^2 = v0^2 + 2as with s = 0.01 m

(5.05*10^5)^2 = (1.06*10^5)^2 + 2*0.01*a
a = 24.37*10^10/(2*0.01)
a = 1.2185*10^13 m/s^2

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