A 75-m-long train begins uniform acceleration from rest. The front of the train has a speed of 23m/s^2 when it passes a railway worker who is standing 200m from where the front of the train started.
a. What will be the speed of the last car as it passes the worker?
a. What will be the speed of the last car as it passes the worker?
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Finding the acceleration, a (m/s²)
u = 0, v = 23.0m/s, d = 200m
v² = u² + 2ad
23² = 0 + (2 x a x 200)
a = 23² /400 = 1.32 m/s²
For the end carriage .. u = 0, d = 275m, a = 1.32 m/s²
v² = u² + 2ad
v² = 0 + (2 x 1.32 x 275)
v² = 726 .. .. .. v = √726 .. .. .. ►v = 26.94 m/s
u = 0, v = 23.0m/s, d = 200m
v² = u² + 2ad
23² = 0 + (2 x a x 200)
a = 23² /400 = 1.32 m/s²
For the end carriage .. u = 0, d = 275m, a = 1.32 m/s²
v² = u² + 2ad
v² = 0 + (2 x 1.32 x 275)
v² = 726 .. .. .. v = √726 .. .. .. ►v = 26.94 m/s