Find the electric Field at a point midway between two charges of +30 nC and +63 nC separated by a distance of

Find the electric Field at a point midway between two charges of +30 nC and +63 nC separated by a distance of 30 cm.
Magnitude of Electric Field
Angle of Electric Field [Enter as an angle between 0 and 360°] degrees

** Need help as soon as possible!! Best answer will be first correct answer, not necessarily the first answer.

Using the formula E = (1/4piE°)(q/d^2) where E° is absoute permitivity of free space

d= 15cm = 0.15m

Here q can be considered as difference of the two charges since they are of same sign

(1/4piE°)=(9*10^9)

Therefore Electric field= (9*10^9)*(33*10^-9)/(0.15*0.15) = 13200 N/C

Along 30 nC charge, Angle with line joining 30nC and 63 nC is 180°

Or else find the field due to each charge and then subtract since they are oppositely directed...

Hope you understood.....!