Please HELP with these GEOMETRY QUestions! 10 points!

Im only in 7th grade. This is like 10th grade stuff, Extra Credit by the way. Please just answer this! First one will get best answer and second one will tie too!

In the diagram of a right triangle ABC, Angle C is the right triangle. Which equation is valid for ABC?
A. COS A= A/B
B. TAN A= B/A
C. SIN A= A/C
D. COS B= A/B

2. In the right triangle ABC, Hypotenuse ab=10, and m angle b= 53. Find AC to the nearest integer
a. 6
b. 8
c. 13
d 15

3.In the diagram CDE, M angle D=90(Right triangle), m angle c= 28, and ED=15 Which equation can be used to find CD?

A. sin 28=15/CD
B Sin 28= CD/15
C. Tan 28= 15/cd
D. Tan 28= CD/15

thank you!

1) SOH-CAH-TOA [Sin opposite hypotenuse-Cos adjacent hypotenuse-Tan opposite adjacent]

Sin A = opposite/hypotenuse =A/C

2) Sum of angles of triangle = 180 degrees
180-(90+53) = 37 degrees for angle A
Cos37 = AC/10
AC = 10Cos37 = 8 to nearest integer

3) Tan 28 =opposite/adjacent = 15/CD, so C)

1) cosA=AC/AB
sinA=CB/AB
cosB=BC/AB
sinB=AC/AB
tgA=CB/AC
tgB=AC/CB

2)cos 37 =0.765414052
cos A= AC/AB
cos 37 = AC/10
10 cos 37 = AC
AC = 7.65414052 = 8 ----> (B.)

3) tg C = ED/DC
angle C=28
tg 28 = 15/DC --> (C.)

1) idk 2) is b sin 53 than whatever you get divide it by 10 3) is e