If a heat engine has an efficiency of 30% and its power output is 600 W, what is the rate of heat input from..

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If a heat engine has an efficiency of 30% and its power output is 600 W, what is the rate of heat input from..

[From: ] [author: ] [Date: 11-05-02] [Hit: ]

He told us that the answer is 2000 W, but he wants a solution. Any explanation or steps to solving the problem would be greatly appreciated. Im so lost!efficiency = 30% = .Heat Input = 600 W / .......

the combustion phase?

My Physics teacher never showed us how to work out problems like this. He told us that the answer is 2000 W, but he wants a solution. Any explanation or steps to solving the problem would be greatly appreciated. I'm so lost!

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efficiency = Power Output / Heat Input

efficiency = 30% = .30

Heat Input = Power Output / efficiency

Heat Input = 600 W / .30

Heat Input = 2000 Watts

1

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