A 2 kg ball is thrown from the top of the 60 m high building with initial velocity 40 m=s at an angle of
60 deg. Find:
a) The time it takes the ball to reach the ground.
b) the distance (horizontal) it travels before hitting the ground.
c) the velocity (total) of the ball when it hits the ground.
d) maximum height the ball will reach.
From energy theorems, find:
e) the work done by the gravity (starting from top of the building until it hits the ground)
f) the initial kinetic energy of the ball.
g) the final kinetic energy of the ball.
h) the final velocity of the ball (show your work).
60 deg. Find:
a) The time it takes the ball to reach the ground.
b) the distance (horizontal) it travels before hitting the ground.
c) the velocity (total) of the ball when it hits the ground.
d) maximum height the ball will reach.
From energy theorems, find:
e) the work done by the gravity (starting from top of the building until it hits the ground)
f) the initial kinetic energy of the ball.
g) the final kinetic energy of the ball.
h) the final velocity of the ball (show your work).
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a) 8.509 sec
b) 170.17 meters
c) 52.69 m/s
d) 121.22 meters above ground level
e) Wg = m*g*h = 2*9.8*60 = 1176 J
f) KEi = ½m*V² = .5*2*60² = 3600 J
g) KEf = KEi + Wg = 4776 J
h) Same as (c)
b) 170.17 meters
c) 52.69 m/s
d) 121.22 meters above ground level
e) Wg = m*g*h = 2*9.8*60 = 1176 J
f) KEi = ½m*V² = .5*2*60² = 3600 J
g) KEf = KEi + Wg = 4776 J
h) Same as (c)