Calculus/integral help

I'm not exactly sure how to do this. The integral from 1 - 2 of (x^3)dx.

By the power rule, the integral of x^3 dx, F(x) is just 1/4x^4. By the FTC, going from 1 to 2 is F(2)-F(1).
So, 1/4(2)^4-1/4(1)^4
=4-1/4
15/4