Assume a ball leaves a cannon with a speed of 42.5m/s. The barrel's angle with respect to the ground is 35.9 degrees (the barrel's muzzle is at ground level). What is the time of flight of the cannon ball? (no mass is given)
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vertical motion
s =ut + 0.5 at^2
0 = 42.5 sin 35.9 t - 0.5 * 9.81 * t^2
0 = t [ 42.5 sin 35.9 - 0.5 * 9.81 * t]
t =0 ( initial starting time]
42.5 sin 35.9 - 0.5 * 9.81 * t =0
t = 5.08s
answer
the time of flight of the cannon ball
s =ut + 0.5 at^2
0 = 42.5 sin 35.9 t - 0.5 * 9.81 * t^2
0 = t [ 42.5 sin 35.9 - 0.5 * 9.81 * t]
t =0 ( initial starting time]
42.5 sin 35.9 - 0.5 * 9.81 * t =0
t = 5.08s
answer
the time of flight of the cannon ball