Point S is between R and T. Use the given information to write equation in terms of X. Solve the equation then find RS and ST.
RS = 2X + 10
ST = X - 4
RT = 21
Thank You
RS = 2X + 10
ST = X - 4
RT = 21
Thank You
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Well... If S is in between R and T, the RS+ ST will equal RT. So... (2X+10) + (X-4) = 21. Then, you combine like terms in the first part because you're just adding all of it. You'll end up with 3X+6=21. You pretty much just solve for X after that by subtracting 6 from 21 and dividing by 3 to get an answer of 5.
In other words,
RS+ST=RT
(2X+10) + (X-4) = 21
3X+6=21
3X= 15
X=5
After that, just plug 5 in for X in RS.. so, 2(5)+10... which equals 20. Therefore, RS=20.
And plug in 5 for the X in ST... (5)-4... which equals 1. Therefore, ST=1.
Hope that helps!
In other words,
RS+ST=RT
(2X+10) + (X-4) = 21
3X+6=21
3X= 15
X=5
After that, just plug 5 in for X in RS.. so, 2(5)+10... which equals 20. Therefore, RS=20.
And plug in 5 for the X in ST... (5)-4... which equals 1. Therefore, ST=1.
Hope that helps!
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RS= ST
BECAUSE S IS IN THE MIDDLE (EXACTLY)
ONE HALF OF THE SEGMANT IS RS, THE OTHER ONE ST THEREFORE RS=ST
ALSO RT IS THE ONE WHOLE SEGMENT
SO
RS + ST = RT
2X + 10 +X - 4 = 21
3X + 6 = 21
3X= 15
X=5
RS= 2(5) +10
RS=20
ST= 5-4
ST= 1
RT=21
20+1 = 21
I DONT KNOW IF I MADE MYSELF CLEAR
BECAUSE S IS IN THE MIDDLE (EXACTLY)
ONE HALF OF THE SEGMANT IS RS, THE OTHER ONE ST THEREFORE RS=ST
ALSO RT IS THE ONE WHOLE SEGMENT
SO
RS + ST = RT
2X + 10 +X - 4 = 21
3X + 6 = 21
3X= 15
X=5
RS= 2(5) +10
RS=20
ST= 5-4
ST= 1
RT=21
20+1 = 21
I DONT KNOW IF I MADE MYSELF CLEAR
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RT = RS + ST
21 = 2x + 10 + x - 4
21 = 3x + 6
27 = 3x
x = 9
RS = 28
ST = 5
21 = 2x + 10 + x - 4
21 = 3x + 6
27 = 3x
x = 9
RS = 28
ST = 5