If a/x + 3/bx = b (ab +3 cannot = 0) then x equals...
Seriously how am I even suppose to start this?
Seriously how am I even suppose to start this?
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does the equation look like this...
a/x + 3x/b = b ... that is, in the 2nd term the x is on top
or like this ...
a/x + 3/(bx) = b ... that is, in the 2nd term, the x is on the bottom
i am going to assume the 2nd one
therefore multiply both sides by bx to get rid of the fraction
ab + 3 = (b^2)x ... so that is why ab + 3 cannot equal zero
so x = (ab + 3) / (b^2)
a/x + 3x/b = b ... that is, in the 2nd term the x is on top
or like this ...
a/x + 3/(bx) = b ... that is, in the 2nd term, the x is on the bottom
i am going to assume the 2nd one
therefore multiply both sides by bx to get rid of the fraction
ab + 3 = (b^2)x ... so that is why ab + 3 cannot equal zero
so x = (ab + 3) / (b^2)
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Sorry .. i asked here and no-one could figure it out.