I am currently trying to learn how to find the derivative using the power rule and so far I understand it until I hit this road block:
(x^2 - 6x + 2) / (2x)
How do you do this using the power rule? The answer is (x^2 - 2)/(2x^2) but I want to know how to get there
(x^2 - 6x + 2) / (2x)
How do you do this using the power rule? The answer is (x^2 - 2)/(2x^2) but I want to know how to get there
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http://www.wolframalpha.com/input/?i=%28…
1/2-1/(x^2) is what they get, which is an identity to your answer, but they got it using the quotent rule.
Click on reference 1, your expression is already in the url, and then click on "show steps" near the integral.
microsoft Math gets the same thing, and it won't show you the steps.
1/2-1/(x^2) is what they get, which is an identity to your answer, but they got it using the quotent rule.
Click on reference 1, your expression is already in the url, and then click on "show steps" near the integral.
microsoft Math gets the same thing, and it won't show you the steps.
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i would use the quotient rule.
which is: vu` - uv` / v^2
u= the top
v= the bottom
u` means derivative of u
v` same thing
or split it up: x^2/2x - 6x/2x + 2/2x
then cancel: 1/2x - 3 + x^-1, then do the derivitive
which is: vu` - uv` / v^2
u= the top
v= the bottom
u` means derivative of u
v` same thing
or split it up: x^2/2x - 6x/2x + 2/2x
then cancel: 1/2x - 3 + x^-1, then do the derivitive