There is a problem on my homework that says let y=3.7. By doing the appropriate algebra and taking the inverse cosine, find the value of theta. I tried plugging in 3.7 on my calculator but it gives me an error. Is there a method to convert 3.7 into a number less than 1? I also need to do this with sin.
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First the sin & cos functions have a max magnitude of 1 so the inverse sin or cos won't work if the magnitude of the argument is >1
You need to figure out what "the appropriate algebra" means. The must be more to the problem.
You need to figure out what "the appropriate algebra" means. The must be more to the problem.
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You can't.
All the values for cosine are between (or equal to) -1 and 1.
So there is no such thing as an inverse cosine of anything greater than 1 or less than -1.
You must have made a mistake in your algebra.
There's no way that's a complete question.
Was there a picture or something?
What is y even supposed to be? y can mean anything.
All the values for cosine are between (or equal to) -1 and 1.
So there is no such thing as an inverse cosine of anything greater than 1 or less than -1.
You must have made a mistake in your algebra.
There's no way that's a complete question.
Was there a picture or something?
What is y even supposed to be? y can mean anything.
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sin and cos limit at 1 if you got a order point to get what sin and cos are need to divide by the distance first then take your arcsin so it will look like this
arcsin{y/[(x^2+y^2)^.5]}
arcsin{y/[(x^2+y^2)^.5]}
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post entire question