A 1.5-kg block slides down a 30º incline with an acceleration of 4.1 m/s². A brief description of the formulas used would greatly help.
-
net force along slope
= 1.5 * 4.1
= 6.15N
weight component // to slope
= mg sin 30
= 1.5 * 9.81 * sin 30
= 7.36 N
weight component // to slope - friction force = net force along slope
7.36 - friction force = 6.15
friction force = 1.21 N
answer
= 1.5 * 4.1
= 6.15N
weight component // to slope
= mg sin 30
= 1.5 * 9.81 * sin 30
= 7.36 N
weight component // to slope - friction force = net force along slope
7.36 - friction force = 6.15
friction force = 1.21 N
answer