One of my friends told me that the sum of interior angles in a pentagon is 6 ( in terms of right angles ).

Can you explain about that ? Thanks.

Your friend is right.

The sum of the internal angles of a pentagon is 540 degrees.
540 degrees = 6 right angles ( ==> 6 X 90 degrees = 540 degrees )

To find the sum of the internal/interior angles of a polygon there is a formula,
(n - 2) 180 where n is the number of sides.

n = 5 , a pentagon has 5 sides
(n - 2) 180
(5 - 2 )180
(3) 180
540

So a pentagon would have 540 degrees.

If the formula is too complicated for you to remember, you can use a pattern =
Add 180 degrees to the next shape.
For example, a triangle has 180 degrees, a quadrilateral has 360 degrees, a pentagon has 540, a hexagon 720, etc.
Each time you add a side you are adding 180 degrees.

I hope it will help you

The sum of any convex polygon's interior angles is 180(n-2), where n is the number of sides that the polygon has. So in the case of a pentagon, n = 5, so the sum of the interior angles is 180(5-2), or 180(3), which is 540. Because a right angle is 90 degrees and 540/90 = 6, 540 degrees is equivalent to six right angles.

If you want to figure things in terms of right angles instead of degrees, the sum of any convex polygon's interior angles can be written as 2(n-2) right angles, because the number of right angles is simply the number of degrees divided by 90.

A pentagon has five sides. If a line is drawn from the centre to each exterior angle, five individual triangles are formed. Therefore, there will be FIVE internal angles.

If it is a regular pentagon - all exteriot sides are equal - the internal angles will be equal and each will be 72 degrees (360/5).

What he means is that the interior angles are equal to 6 right angles. Since the sum of the interior angles of a pentagon is 540, 540 divided by 6 is 90, which is one right angle.

He is right. The sum of interior angle of an n-sided polygon is (n-2) pi. For pentagon, it is 3 pi.