Locate the corners of an equilateral triangle if the difference of the corners 15 degrees is.
There are two answers: 50 degrees, 65 degrees, 65 degrees
and: 55 degrees, 55 degrees, 70 degrees
Both answers are right, but how do you get the answers? Please explain!
There are two answers: 50 degrees, 65 degrees, 65 degrees
and: 55 degrees, 55 degrees, 70 degrees
Both answers are right, but how do you get the answers? Please explain!
-
I think you mean a isosceles triangle. if yes
Then let one of the corners be none equal angle be x.
x + (x+15) + (x+15) = 180 degrees.
3x + 30 = 180 degrees
x = 150/3
x=15
x+15 = 65
Or
x + (x-15) + (x-15) = 180
3x-30 = 180
x=210/3
x=70
x-15 = 55
Find out which is subtracted from which to get the differsnce and the decide the answer.
Then let one of the corners be none equal angle be x.
x + (x+15) + (x+15) = 180 degrees.
3x + 30 = 180 degrees
x = 150/3
x=15
x+15 = 65
Or
x + (x-15) + (x-15) = 180
3x-30 = 180
x=210/3
x=70
x-15 = 55
Find out which is subtracted from which to get the differsnce and the decide the answer.
-
Let, he 2 equal angles are x. Then the other is x+15 or, x-15
if the other is x+15 then we get x+x+(x+15)=180 => 3x=165 =>x=55
thus, 55,55,(55+15)=70
Again, if it is x-15 then we get x+x+(x-15)=180=> 3x=195=>x=65
thus, 65,65,50
if the other is x+15 then we get x+x+(x+15)=180 => 3x=165 =>x=55
thus, 55,55,(55+15)=70
Again, if it is x-15 then we get x+x+(x-15)=180=> 3x=195=>x=65
thus, 65,65,50
-
x= angle 1
x+15=angle 2
x+15=angle 3
x+x+15+x+15=180
or
x= angle 1
x-15=angle 2
x-15= angle 3
x+x-15+x-15=180
x+15=angle 2
x+15=angle 3
x+x+15+x+15=180
or
x= angle 1
x-15=angle 2
x-15= angle 3
x+x-15+x-15=180