How many moles of ag contain 4.49 x 10 to the 23rd atoms ag

[From: ] [author: ] [Date: 11-09-15] [Hit: ]

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One mole contains 6.022x10^23 atoms Therefore 4.49x10^23 / 6.022x10^23 = 0.746 or
7.46x10^-1

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