Write the equalibrium equation for the ionization of acetic acid. What would happen to the concentration of acetic acid if sodium acetate is added to the solution? Suggest a method to verify your conclusion.
Thanks
Thanks
-
You can write it any of these ways:
HC2H3O2 <------------> H+ + C2H3O2-
or, if you're an organic chemist
CH3COOH <-----------------> H+ + C2H3O2-
A Bronsted-Lowry enthusiast would write
HC2H3O2 + H2O <----------------> H3O+ + C2H3O2-
or
CH3COOH + H2O<------------> H3O+ + CH3COO-
If you added sodium acetate, you would be increasing the concentration of acetate ion, the C2H3O2-, and, from Lechatelier's principle, this would drive the reaction to the left increasing the concentration of molecular HC2H3O2. It would lower the concentration of H+ and therefore lower the pH, which is how you could verifty it - use a pH meter and check the pH before and after you add the sodium acetate.
HC2H3O2 <------------> H+ + C2H3O2-
or, if you're an organic chemist
CH3COOH <-----------------> H+ + C2H3O2-
A Bronsted-Lowry enthusiast would write
HC2H3O2 + H2O <----------------> H3O+ + C2H3O2-
or
CH3COOH + H2O<------------> H3O+ + CH3COO-
If you added sodium acetate, you would be increasing the concentration of acetate ion, the C2H3O2-, and, from Lechatelier's principle, this would drive the reaction to the left increasing the concentration of molecular HC2H3O2. It would lower the concentration of H+ and therefore lower the pH, which is how you could verifty it - use a pH meter and check the pH before and after you add the sodium acetate.
-
HC2H3O2 --> H+ + C2H3O2-
1) adding NaC2H3O2 would cause a huge production of C2H3O2- but not from the acetic acid, this would remain as acetic acid due to the common ion effect and that NaC2H3O2 is much more soluble than HC2H3O2
NaC2H3O2 --> Na+ + C2H3O2-, the pH will be basic whereas the pH of acetic acid dissociation will be acidic
NaC2H3O2 + H2O --> HC2H3O2 + Na+ + OH-, pH > 7
HC2H3O2 + H2O --> H+ + C2H3O2-, pH < 7
1) adding NaC2H3O2 would cause a huge production of C2H3O2- but not from the acetic acid, this would remain as acetic acid due to the common ion effect and that NaC2H3O2 is much more soluble than HC2H3O2
NaC2H3O2 --> Na+ + C2H3O2-, the pH will be basic whereas the pH of acetic acid dissociation will be acidic
NaC2H3O2 + H2O --> HC2H3O2 + Na+ + OH-, pH > 7
HC2H3O2 + H2O --> H+ + C2H3O2-, pH < 7