How many moles of chlorine atoms are present in a 9.2 x 10 ^ -2 g sample of zirconium(IV) chloride, ZrCl subscript 4?
Please step by step explanations and answers please please thank you so much <3
Please step by step explanations and answers please please thank you so much <3
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1 mole of ZrCl4 = 233.04 g
9.2 x 10^-2 g ZrCl4 x 1 mol / 233.04 g = 3.948 x 10^-4 mol of ZrCl4
Since there are 4 Cl atoms for each molecule,
4(3.948 x 10^-4 mol) = 1.579 x 10^-3 mol Cl
Or 1.6 x 10^-3 mol Cl
9.2 x 10^-2 g ZrCl4 x 1 mol / 233.04 g = 3.948 x 10^-4 mol of ZrCl4
Since there are 4 Cl atoms for each molecule,
4(3.948 x 10^-4 mol) = 1.579 x 10^-3 mol Cl
Or 1.6 x 10^-3 mol Cl