Determine the pH of these solutions
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Determine the pH of these solutions

[From: ] [author: ] [Date: 11-09-15] [Hit: ]
For pH from [OH^-], you must know that [H^+][OH^-] = 1 x 10^-14.In C),[H^+] = (1 x 10^-14)/(1 x 10^-2) = 1 x 10^-12Thus,You should be able to do the rest without further help.Hope this is helpful to you.......
A) [H+] = 1 * 10^-6M
B) [H+] = 0.00010M
C) [OH-] = 1 * 10^-2M
D) [OH-] = 1 * 10^-11M

Thanks!

-
These are all pretty easy. pH = -log[H^+]

Put the value for the [H^+] in your calculator and press the log button. The number you get will be negative. Now press the +/- button and you will obtain your answer.

Example: log(1 * 10^-6) = -6
press +/- and pH = 6

For pH from [OH^-], you must know that [H^+][OH^-] = 1 x 10^-14. Calculate [H^+] from [OH^-] by rearranging the equation to:

[H^+] = (1 x 10^-14)/[OH^-]

In C), for example:

[H^+] = (1 x 10^-14)/(1 x 10^-2) = 1 x 10^-12 Thus,

pH = -log(1 x 10^-12) = 12

You should be able to do the rest without further help.

Hope this is helpful to you. JIL HIR
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