what is the molarity of sulfate ions?
Answer in units of M
Answer in units of M
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1 mol Al2(SO4)3 releases 3 mol SO42- in solution.
0.046 mol Al2(SO4)3 x (3 mol SO42- / 1 mol Al2(SO4)3) = 0.138 mol SO42-
M = mol / L = 0.138 mol / 0.638 L = 0.216 M SO42-
0.046 mol Al2(SO4)3 x (3 mol SO42- / 1 mol Al2(SO4)3) = 0.138 mol SO42-
M = mol / L = 0.138 mol / 0.638 L = 0.216 M SO42-