Chemistry Please HELP!
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Chemistry Please HELP!

[From: ] [author: ] [Date: 11-09-17] [Hit: ]
Can anybody tell me how to find the neutron on those because i dont really understand it.How do I identify an these element?202 ..........
Thanks a lot to whoever answers I'm just trying to do my homework but i don't understand it much. I would greatly appreciate it if you could do at least one. Thanks again

Ok so I know the atomic mas for Al is 26.98 which would round to 27 and it has 13 protons and electrons. And I know 27-13=14 so Al should have 14 neutrons.
What I don't know is how to find the neutrons in the ones that are like 27Al or 32S.
Can anybody tell me how to find the neutron on those because i don't really understand it.

How do I identify an these element?
202
......X
80

Can you explain to me how to get these answers?
90..............0......
.....Sr----->...e.....+?
38..............1......
........and
210............4..........
..Ra----->..He ...+....?
88..............2..........

-
most (not all, but most) elements are mixtures of isotopes
so you cannot round off average atomic mass to get mass number because most elements have more than one mass number among the mix of isotopes
however
if you are given both mass number and atomic number you can identify the particular isotope
202/80 X ---> 202/80 Hg or mercury-202

90/38 Sr ---> 0/1 e + 90/37 X so that is 90/37 Rb or rubidium 90
however 0/1 e is a positron, the antiparticle of an electron
this is an unusual radioactive emission
perhaps it should be 0/-1 e, a beta particle - much more common
if so
90/38 Sr ---> 0/-1 e + 90/39 X which is 90/39 Y or yttrium-90

either way note that the top numbers must add up and so must the bottom numbers

210/88 Ra ---> 4/2 He + 206/86 X which is 206/86 Rn or radon-206

-
Al-27 contains 13 protons (atomic number) and must contain 27 - 13 = 14 neutrons.
S-32 contains 16 protons (atomic number) and must contain 32 - 16 = 16 neutrons.

202/80 X has an atomic number of 80, which makes the element to be Hg, mercury.

The sum of the superscripts must add up to be the same on each side of a nuclear equation; the same goes for the subscripts.

90/38 Sr -----> 0/-1 e + 90/39 Y (the element is Y because the atomic number must be 39)

210/88 Ra -----> 4/2 He + 206/86 Rn (the element is Rn because the atomic number must be 86)
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