A ball is thrown into the air and follows a parabolic trajectory. Point A is the highest point..HELP!!!

A ball is thrown into the air and follows a parabolic trajectory. Point A is the highest point in the trajectory and Point B is a point as the ball is falling back to the ground. Choose the correct relationship between the speeds and the magnitude of the acceleration at the two points.


A. VA > VB and aA = aB

B. VA < VB and aA > aB

C. VA = VB and aA ≠ aB

D. VA < VB and aA = aB

I assume that you are talking about velocity and acceleration in the vertical direction. (If the ball is thrown straight up, that's all there is, anyway.) The vertical acceleration is constant, due to gravity, so aA = aB from the time the ball is thrown until it hits the ground. When the ball is thrown, its velocity is maximum and starts decreasing. At the highest point, the velocity (in the vertical direction at least) is zero. Then the velocity starts increasing until it hits something. So VA < VB and aA = aB (answer D).

A projected body has only horizontal velocity when it is at the highest point. Hence the velocity is less at point A when compared to point B which has both horizontal and vertical velocities. Acceleration is same for both the bodies.

I must say, your intelligence level is that of a piece of rat feces. Unquestionably, you must be destroyed.

D

D. VA < VB and aA = aB