What volume (in mL) of a 0.6758 M solution of CaCl2 contains 1.934 g of the solute?
Do not include units in your answer.
Do not include units in your answer.
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0.6758 M means that there are .6758 moles of this CaCl2 in 1000 ml of solution.
If you find the molar mass of CaCl2 then you can arrange a formula, in which you can get the units to cancell, except the desired units wich are millileters, even though the question states to not include these units in the answer. Always start with the given in the problem. Work from there. Don'f forget to find the molar mass of the chemical in question.
1000ml/.6758 mol x 1 mol CaCl2/110.98 g CaCl2 x 1.934 g CaCl2 = 25.7865690215253051
limiting the answer by your least accurate measurement of 4 sig. figs. it is 25.79 ml or just 25.79.
Show your work and show your units cancelling.
If you find the molar mass of CaCl2 then you can arrange a formula, in which you can get the units to cancell, except the desired units wich are millileters, even though the question states to not include these units in the answer. Always start with the given in the problem. Work from there. Don'f forget to find the molar mass of the chemical in question.
1000ml/.6758 mol x 1 mol CaCl2/110.98 g CaCl2 x 1.934 g CaCl2 = 25.7865690215253051
limiting the answer by your least accurate measurement of 4 sig. figs. it is 25.79 ml or just 25.79.
Show your work and show your units cancelling.