Calculus (Limits) Help
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Calculus (Limits) Help

[From: ] [author: ] [Date: 11-09-19] [Hit: ]
that lim(x→4) f(x) = 7.I hope this helps!......
I don't understand this homework problem:

If 4x - 9 ≤ f(x) ≤ x^2 - 4x +7 for x ≥ 0, find lim x--> 4 f(x)

The f(x) in the middle is throwing me off. What's supposed to be there so I can solve it?

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Knowing what f equals is irrelevant for this question.

Since lim(x→4) (4x - 9) = 7 = lim(x→4) (x^2 - 4x + 7), we conclude by the Squeeze Law
that lim(x→4) f(x) = 7.

I hope this helps!
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keywords: Help,Limits,Calculus,Calculus (Limits) Help
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