Can anyone please help me to find the molecular formula for this problem?? Ill give ten points thanks!?
A 3.000g sample of a gaseous compound was found to contain 2.560g of carbon and 0.440g of Hydrogen. a)What is the simplest formula of the compound?b) The molecular weight of the compound found was found to be 42.08. What is the molecular formula of the compound?
A 3.000g sample of a gaseous compound was found to contain 2.560g of carbon and 0.440g of Hydrogen. a)What is the simplest formula of the compound?b) The molecular weight of the compound found was found to be 42.08. What is the molecular formula of the compound?
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Determine moles of C and H:
carbon: 2.560 g / 12.011 g/mol = 0.213138 mol
hydrogen: 0.440 g / 1.008 g/mol = 0.436508 mol
Determine smallest whole number ratio:
carbon: 0.213138 / 0.213138 = 1
hydrogen: 0.436508 / 0.213138 = 2.05
empirical formula = CH2
"empirical formula weight" = 14.0
42.08 / 14 = 3
molecular formula = C3H6
carbon: 2.560 g / 12.011 g/mol = 0.213138 mol
hydrogen: 0.440 g / 1.008 g/mol = 0.436508 mol
Determine smallest whole number ratio:
carbon: 0.213138 / 0.213138 = 1
hydrogen: 0.436508 / 0.213138 = 2.05
empirical formula = CH2
"empirical formula weight" = 14.0
42.08 / 14 = 3
molecular formula = C3H6
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2.56/12= .213
.44/1= .44
.44/.213= 2
Empirical Formula= CH2
42.08/14=3
Molecular Formula= C3H6 Cyclopropane
.44/1= .44
.44/.213= 2
Empirical Formula= CH2
42.08/14=3
Molecular Formula= C3H6 Cyclopropane