A student placed 19.5 grams of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100.- ML mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 30.0-mL sample of this glucose solution was diluted to 0.500L . How many grams of glucose are in 100. mL of the final solution?
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Well, we have 19.5 grams in that original 100mL solution, and then we take 30% of that solution, so
19.5 * .3 = 5.85 grams. There are 5.85 grams in the .5L solution, and we want to know how much are in .1L, so we divide by 5: 5.85/5 = 1.17 grams
19.5 * .3 = 5.85 grams. There are 5.85 grams in the .5L solution, and we want to know how much are in .1L, so we divide by 5: 5.85/5 = 1.17 grams