Mathematics: Calc 3, Parametric Equations, intersection of curves
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Mathematics: Calc 3, Parametric Equations, intersection of curves

[From: ] [author: ] [Date: 11-09-22] [Hit: ]
y,let x = rcos(u), z = rsin(u) ... angle u is in (x,......
Find parametric equations for the curve of intersection of the circular cylinder x^2 + z^2 = 1 and the hyperbolic paraboloid z = x^2 - y^2.

I have no idea how to do this.

10 points for the best explanation.

Thanks.

Z.

-
Locus of R(x,y,z) is points of intersection:
r = |OR|

for cylinder;
x^2 + z^2 = 1
let x = rcos(u), z = rsin(u) ... angle u is in (x,z) plane

[rcos(u)]^2 + [rsin(u)]^2 = 1
==> r^2 =1 i.e. |OR| is of unit measure or r = 1 .. your cylinder is a circle?

for parabaloid;
z = x^2 - y^2
rsin(u) = [rcos(t)]2 - [rsin(t)]^2
rcos(u) = r^2 [cos(t)^2 -sin(t)^2] ...but cos(t)cos(t) -sin(t)sin(t) = cos(2t)
1.cos(u) = 1. cos(2t)
cos(u) = cos(2t) , u = ± 2t

x = cos(t), y = sin(t), z = ± sin(2t)

1^2 = sin(2t)^2 since r^2 =x^2 + y^2 + z^2 in general
2t = π (1± 2n)
t = π/2 (1± 2n)

x = cos{π/2 (1± 2n)} = 0 for all n
y = sin{π/2 (1± 2n)} = { -1, 1}
z = ± sin{π (1± 2n)} = 0 for all n

the cylinder (or circle since r^2 =1 here) intersects the hyperbaloid at two points
(0,-1,0) and (0,1,0)
1
keywords: Calc,Equations,intersection,Mathematics,Parametric,curves,of,Mathematics: Calc 3, Parametric Equations, intersection of curves
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