A barge is in a rectangular lock on a freshwater river. The lock has length 64.0m and width 23.5m, and the steel doors on each end are closed. With the barge floating in the lock, a load of scrap metal weighing 2.75×106N is put onto the barge. The metal has density 8100kg/m^3.
1.When the load of scrap metal, initially on the bank, is placed onto the barge, what vertical distance does the water in the lock rise?
2.The scrap metal is now pushed overboard into the water. Does the water level in the lock rise, fall, or remain the same?
3.If it rises or falls, by what vertical distance does it change?
I don't really even understand what a lock or barge is.
1.When the load of scrap metal, initially on the bank, is placed onto the barge, what vertical distance does the water in the lock rise?
2.The scrap metal is now pushed overboard into the water. Does the water level in the lock rise, fall, or remain the same?
3.If it rises or falls, by what vertical distance does it change?
I don't really even understand what a lock or barge is.
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A lock is a body of water contained between 2 sets of openable gates, used to transport cargos by water using different levels, like the Panama Canal. Considering an upstream direction, the vessel is placed in the lock, when the upstream gates are shut. The downstream gates are then closed, and water from upstream is allowed to flow through a pipe into the lock. It continues to flow until the water level in the lock is at the level of the upstream water, at which time the upstream gates are opened, and the vessel continues on up the stream, now elevated to a new level.
Going downstream is a reversal of the above sequence, and the vessel continues lower.
A barge is just a large, flat bottomed boat propelled by a tug, used to transport goods on water.
The lock area is (64 x 23.5) = 1,504m^2.
When the steel is placed on the barge, an extra weight of water equal to the weight of the steel is displaced. So weight displaced = 2,750,000N. That's a mass of (2,750,000/9.8) = 280,612.24kg.
The volume of the water displaced = (280,612.24/1,000) = 280.61m^3.
(280.61/ 1,504) = height increase of 0.1866 metre in water level.
When the steel is pushed into the water of the lock, it only displaces its own volume of water. So, the water level increase will fall.
(280,612.24kg./8100) = 34.6435m^3of steel.
(34.6435/1,504) = water height of 0.023 metres.
Difference in water height produced = (0.1866 - 0.023) = 0.1636m. between the steel being on the barge and the steel being in the water.
Going downstream is a reversal of the above sequence, and the vessel continues lower.
A barge is just a large, flat bottomed boat propelled by a tug, used to transport goods on water.
The lock area is (64 x 23.5) = 1,504m^2.
When the steel is placed on the barge, an extra weight of water equal to the weight of the steel is displaced. So weight displaced = 2,750,000N. That's a mass of (2,750,000/9.8) = 280,612.24kg.
The volume of the water displaced = (280,612.24/1,000) = 280.61m^3.
(280.61/ 1,504) = height increase of 0.1866 metre in water level.
When the steel is pushed into the water of the lock, it only displaces its own volume of water. So, the water level increase will fall.
(280,612.24kg./8100) = 34.6435m^3of steel.
(34.6435/1,504) = water height of 0.023 metres.
Difference in water height produced = (0.1866 - 0.023) = 0.1636m. between the steel being on the barge and the steel being in the water.