A hockey puck is sliding down an inclined plane with angle θ = 10.0°.
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A hockey puck is sliding down an inclined plane with angle θ = 10.0°.

[From: ] [author: ] [Date: 11-09-22] [Hit: ]
In retrospect, I should have shown some work like I did for other people, so sorry for that, but Im glad what I gave you helped.......
A hockey puck is sliding down an inclined plane with angle θ = 10.0° as shown in the figure below. If the puck is moving with a constant speed, what is the coefficient of kinetic friction between the puck and the plane?

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I won't do your homework, but I'll help.

Draw a free body diagram. Three forces should be in play if you've drawn it correctly; weight, friction, and a normal force. Use your equations of statics (constant velocity implies equilibrium, since acceleration is zero) and set forces in the x- and y- directions to zero. Frictional force is a function of normal force, so plug what you derived the normal force in one coordinate direction into your second direction, and solve for the coefficient of kinetic friction.

If you got 0.176 like I did when I computed it, you're on the right track.

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Thanks. In retrospect, I should have shown some work like I did for other people, so sorry for that, but I'm glad what I gave you helped.

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