Find the distance traveled before coming to rest

A 2-kg block is projected at 3 m/s up a 15º incline which µk=0.2.

*No need to fully work out the problem, I am able to. Would just like help setting up formulas including those variables of m=2 kg, v=3 m/s, ø=15º, and µk=0.2. I understand that this question has to do with Work-Energy Theorem as well, if you have any other parts of formulas, if you'd include a "legend" of some sort to identifiy what each part is, i'd greatly appreciate it and would help alot. Thanks!*

you can use kinematics:

the forces acting on the block are mg sin(theta) down the plane and u mg cos(theta) down the plane

so

-mg sin(theta) - u mg cos(theta) =ma or a=-g(sin(theta)+u cos(Tehta)

then find the distance up the plane using:

vf^2=v0^2 + 2ad

vf=final velocity
v0=initial velocity = 3m/s
a=the acceleration you just computed
d=distance to be solved for

substitute values and solve for d

you can also use the work energy theorem

the work done on the box equals the change in KE

the box starts with 1/2 mv^2 KE (m=2kg and v=3m/s) and ends with zero KE

the work done on the box = force x d, and the sum of forces are mgsin(theta)+u mg cos(theta)

so 1/2 mv^2 = mg d(sin(theta)+u cos(Theta))

and you should get the same answer as above