What is pH of the 0.5L of HCl 0.5M mixed with 0.5L of H2SO4 0.0048M

No. of moles of H+ in HCl = 0.5L x 0.5M = 0.25mole
No. of moles of H+ in H2SO4 = 2(0.5L x 0.0048M) = 0.0048mole
(Note: 1 mole H2SO4 = 2moles H+)
Total No. of moles of H+ = 0.2548mole and total Volume = 1L. Hence [H+] = 0.2548mol/L
pH = -log[H+] = -log(0.2548) = 0.5938 Hence pH ~ 0.60