A mass starts at rest the top of a quarter circular, frictionless ramp of radius 11.5 meters. What is the object's speed at the bottom of the ramp in m/s?
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Same as if you just dropped it 11.5 meters
v = √(2gh) = √(2•9.8•11.5)
v = √(2gh) = √(2•9.8•11.5)