A skateboarder with a mass of 65 Kg who is initially at rest, starts to roll down a hill with a 15 degree incline. If the average force of friction on the skateboard is 35N, what distance has he skated when he reaches a speed of 7m/s?
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F = m*g*sin15° - 35 = 161.36 N
a = F/m = 2.483 m/s²
D = V²/(2a) = 7²/(2*2.483) = 9.87 m
a = F/m = 2.483 m/s²
D = V²/(2a) = 7²/(2*2.483) = 9.87 m