8. A hawk flies in a horizontal arc of radius 15 m
at a constant speed of 6 m/s.
Find its centripetal acceleration.
Answer in units of m/s^2----------------------------the answer is 2.4, I just can't figure out #9 below
9. (part 2 of 2)
It continues to fly along the same horizon-
tal arc but increases its speed at the rate of
1.02 m/s2.
Find the magnitude of acceleration under
these new conditions.
Answer in units of m/s2
at a constant speed of 6 m/s.
Find its centripetal acceleration.
Answer in units of m/s^2----------------------------the answer is 2.4, I just can't figure out #9 below
9. (part 2 of 2)
It continues to fly along the same horizon-
tal arc but increases its speed at the rate of
1.02 m/s2.
Find the magnitude of acceleration under
these new conditions.
Answer in units of m/s2
-
The trick here is that they want the answer for just after the acceleration starts; the speed is still 6 m/s, and the radial a = 2.4. The tangential a is given as 1.02 m/s², so just add the 2 vectors:
Atot = √[2.4² + 1.02²] = 2.61 m/s²
Atot = √[2.4² + 1.02²] = 2.61 m/s²