Graph the system of inequalities. Clearly label the boundary lines. Then use your graph to identify any two points that are solutions to the system. Show and explain your work.
{y > 1/4x - 2}
{x + y ≤ 3}
I believe the solution to the inequality is:
{x<4y+8}
{x≤-y+3}
But, i could be incorrect.
If you could please explain to me how to do this, and show me step by step. You would be helping me very much. Just in need of finding the two points.
{y > 1/4x - 2}
{x + y ≤ 3}
I believe the solution to the inequality is:
{x<4y+8}
{x≤-y+3}
But, i could be incorrect.
If you could please explain to me how to do this, and show me step by step. You would be helping me very much. Just in need of finding the two points.
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{y > 1/4x - 2}
{x + y ≤ 3}
To solve a system of inequalities, graph each line and shade the side that makes the statement true. Then the part that is in both shaded regions is the solution.
1) y> (1/4)x-2
This line has a y intercept of -2 and a slope of 1/4. Graph the line, starting at -2 on the y axis, then move up 1, right 4. Put another point at (4,-1). This is a dotted line. Then shade above the line (for >)
2) x+y<=3
Y<=-x+3
This line has a y intercept of 3, with slope=-1. Start at 3 on the y axis, move down 1, right 1. Put a point at (1,2). This is a solid line. Shade below.
The solution is the part that is shaded twice, a large angle shape. Any point in the shaded region is a solution.
One point is (0,0) . Another is (-2,2)
Hoping this helps!
{x + y ≤ 3}
To solve a system of inequalities, graph each line and shade the side that makes the statement true. Then the part that is in both shaded regions is the solution.
1) y> (1/4)x-2
This line has a y intercept of -2 and a slope of 1/4. Graph the line, starting at -2 on the y axis, then move up 1, right 4. Put another point at (4,-1). This is a dotted line. Then shade above the line (for >)
2) x+y<=3
Y<=-x+3
This line has a y intercept of 3, with slope=-1. Start at 3 on the y axis, move down 1, right 1. Put a point at (1,2). This is a solid line. Shade below.
The solution is the part that is shaded twice, a large angle shape. Any point in the shaded region is a solution.
One point is (0,0) . Another is (-2,2)
Hoping this helps!
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S: Make the equations Y=1/4X-2 and Y=3-X Set X to 0 in each case. Therefore we have Y=0-2 and Y = 3-0=3; Therefore the range of Y is Y is greater than -2 and Y is less than or equal to +3, This means you can graph the Y axis at +3 and -2 and show Y must be greater than 2 and less than or equal to a +3.
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sketch 2 linear graphs and shade the feasible region