Can someone help me with this sequence question

a1= 1/(2-1/2)), a2= 2/(3-1/3), a3= 3/(4-1/4), a4= 4/(5-1/5), a5= 5/(6-1/6)

Can someone help me find the formula for this sequence?

I got (n+1)/((n+2)-(1/(n+2))), however this answer is incorrect.

Can someone please help

Thank you all!

The sequence for term a(n) would be:

a(n) = n / ((n+1) - 1/(n+1))

Best of luck!

(n+1)/((n+2)-(1/(n-1)))

try an= n/ [(n+1)-(1/(n+1))]