3.01 x 10^23 atoms of zinc?
can you explain how to do this
also how many protons are in 648.7 g of krypton?
can you explain how to do this
also how many protons are in 648.7 g of krypton?
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3.01 x 10^23 atoms Zn x (1 mol / 6.02 x 10^23 atoms) = 0.500 mol Zn
648.7 g Kr x (1 mol / 83.80 g ) = 7.74 mol Kr
7.74 mol Kr x (6.02 x 10^23 atoms / 1 mol) = 4.66 x 10^24 atoms Kr
4.66 x 10^24 atoms Kr x (36 protons / 1 atom) = 1.68 x 10^26 protons
648.7 g Kr x (1 mol / 83.80 g ) = 7.74 mol Kr
7.74 mol Kr x (6.02 x 10^23 atoms / 1 mol) = 4.66 x 10^24 atoms Kr
4.66 x 10^24 atoms Kr x (36 protons / 1 atom) = 1.68 x 10^26 protons
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3.01 x 10^23 can also be 3.01e23 which will be easier to put in your calculator.
3.01e23 l 1 mole of Zn
------------l ------------------
...............l 6.02e^23 <--- avogadros number must be used when using moles
multiply 3.01e23 by 1
then divide by 6.02e^23
right now i do not have a calculator with me but once you have completed these step you will have your answer.
the number of protons of any element will always stay the same unless it's an isotope. so it will always have
don't forget to right "moles of Zn" after your answer. NO NAKED NUMBERS!!
3.01e23 l 1 mole of Zn
------------l ------------------
...............l 6.02e^23 <--- avogadros number must be used when using moles
multiply 3.01e23 by 1
then divide by 6.02e^23
right now i do not have a calculator with me but once you have completed these step you will have your answer.
the number of protons of any element will always stay the same unless it's an isotope. so it will always have
don't forget to right "moles of Zn" after your answer. NO NAKED NUMBERS!!