NH4SH(s) yields NH3(g) + H2S(g) is the equation.
When solid NH4SH is placed in a closed flask at 28 degrees C, the solid dissociates according the above equation. THe total pressure of the equilibrium mixture is 0.766 at. Determine Kp at this temp.
It says the answer is 0.147. How do i get this?
When solid NH4SH is placed in a closed flask at 28 degrees C, the solid dissociates according the above equation. THe total pressure of the equilibrium mixture is 0.766 at. Determine Kp at this temp.
It says the answer is 0.147. How do i get this?
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Kp = P(NH3) X P(H2S)
Since the two gases are formed in equimolar amounts, the total pressure at equilibrium is twice the pressure of each gas. So, P(NH3) = P(H2S) = 0.766/3 = 0.383
Kp = 0.383 X 0.383 = 0.147
Since the two gases are formed in equimolar amounts, the total pressure at equilibrium is twice the pressure of each gas. So, P(NH3) = P(H2S) = 0.766/3 = 0.383
Kp = 0.383 X 0.383 = 0.147
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Burbble burbble?