Use the Henderson-Hasselbalch equation. pKb NH3= 4.75
Please show all work!! Thanks a bunch! :D
Please show all work!! Thanks a bunch! :D
-
pOH= pKb+lg([NH4(+)]/[NH3])
= 4.75+lg(0.45/0.75)
= 4.53
pH= 14-pOH
= 9.47
I hope this helps and feel free to send me an e-mail if you have any doubts!
= 4.75+lg(0.45/0.75)
= 4.53
pH= 14-pOH
= 9.47
I hope this helps and feel free to send me an e-mail if you have any doubts!