Compute the inverse of the following. Use the Euclidian algorithm.
(x2 + x)-1 mod (x − 1)Q[x]
(x2 + x)-1 mod (x − 1)Q[x]
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By Euclidean Algorithm in Q[x],
x^2 + x = (x + 2)(x - 1) + 2.
So, x^2 + x = 2 mod.
==> (x^2 + x)^(-1) = 1/2 mod.
That is, (x^2 + x)^(-1) = 1/2 in Q[x]/.
I hope this helps!
x^2 + x = (x + 2)(x - 1) + 2.
So, x^2 + x = 2 mod
==> (x^2 + x)^(-1) = 1/2 mod
That is, (x^2 + x)^(-1) = 1/2 in Q[x]/
I hope this helps!