What is the magnitude of the normal force of the table on the upper magnet

Two strong magnets on opposite sides of a small table are shown. The long-range attractive force between the magnets keeps the lower magnet in place. Suppose the weight of the table is 19.3 N, the weight of each magnet is 5.91 N, and the magnetic force on the lower magnet is 2.61 times its weight.

I have found the magnitude of the force of the lower magnet on the upper magnet to be 1.54e+01 N and the same result for the force of the lower magnet on the upper magnet.

But am stuck on finding the magnitude of the normal force of the table on the upper magnet.

Could anyone help?

Much appreciated.

Here's the diagram: http://i.imgur.com/BaLL3.png

Since the system is in equilibrium all the forces are balanced .. the normal upward force on the magnet must balance the downward forces from the magnet on the table.

Downward forces are ..
magnet weight + attraction to lower magnet = 5.91N + 15.43N .. .. ►21.34 N