Find all solutions of the equation 2 sin 2(theta) - sq. rt (3) = 0 on the interval [0,2(pie)]? Help Please!!
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Find all solutions of the equation 2 sin 2(theta) - sq. rt (3) = 0 on the interval [0,2(pie)]? Help Please!!

[From: ] [author: ] [Date: 11-10-31] [Hit: ]
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Trig is way too complicated for me. Could someone please show me how to do this step by step?
Appreciate it! and Thank you!

-
2 sin 2(θ) - √3 = 0
sin 2(θ)= (√3)/2
2(θ)=60
(θ)=30
Since:
Sin(π –θ)=sin(θ)
Then:
Sin(π –2θ)=sin(2θ)
π –2θ=60
2θ= π –60
2θ=120
θ=60
R: 30 and 60
A you also know:
sin(θ+π/2)= - cos(θ)
sin(θ+π)= - sin(θ)
sin(θ+2π)= sin(θ)
1
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