Trig is way too complicated for me. Could someone please show me how to do this step by step?
Appreciate it! and Thank you!
Appreciate it! and Thank you!
-
2 sin 2(θ) - √3 = 0
sin 2(θ)= (√3)/2
2(θ)=60
(θ)=30
Since:
Sin(π –θ)=sin(θ)
Then:
Sin(π –2θ)=sin(2θ)
π –2θ=60
2θ= π –60
2θ=120
θ=60
R: 30 and 60
A you also know:
sin(θ+π/2)= - cos(θ)
sin(θ+π)= - sin(θ)
sin(θ+2π)= sin(θ)
sin 2(θ)= (√3)/2
2(θ)=60
(θ)=30
Since:
Sin(π –θ)=sin(θ)
Then:
Sin(π –2θ)=sin(2θ)
π –2θ=60
2θ= π –60
2θ=120
θ=60
R: 30 and 60
A you also know:
sin(θ+π/2)= - cos(θ)
sin(θ+π)= - sin(θ)
sin(θ+2π)= sin(θ)