Ax + By = C help??????????????????????????????????

The question is "Write the equation of each line in the form Ax + By =C"
I was given the x and y intercepts.
X-Int is 4 and Y-int is -2. How do I do this question?

The value of the X intercept is when the value of Y =0. So when X = 4, Y =0. Or (4,0) is on the line.
The value of the Y intercept is when the value of X =0. Therefore when X=0, Y = -2. Or (0,-2) is on the line.
Knowing the two points on the straight line, (4,0) and (0,-2) we can find the equation. Since the answer is supposed to be in the form Ax + By = C. we can substitute the points on this line into this equation since the points must satisfy the equation.
Therefore, A(4) +B(0) = C
Also A(0) +B(-2) = C.
To find the constants A, B, C we must solve the above two equations. Fortunately, since the Right Hand Side is the same "C" in both equations, we don't need 3 equations to solve for the 3 constants.
Therefore, 4A + 0 = C or, A = C/4
and 0 -2B =C or, B = -C/2
Substituting the values of A & B from above into Ax + By =C we get,
Cx/4 - Cy/2 =C
Dividing both sides of equation by C, we have {Remember as long as the operation you perform on both sides is the same, the equation doesn't change.}
x/4 - y/2 =1
Mutiplying both sides of equation by 4 we get, x -2y =4
There is the answer. Guess what?. It matches the answer in the book!!

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