Help with math homework please

Okay. So here is the problem :

The sum of the digits of a two-digit number is 14. If the digits are reversed, the number is increased by 18. What is the number?

Please help me solve the problem using two variables and the system of two equations please and thank you. Also, please explain how you got the answer. THANKS.
P.S.
THIS IS SOLVING A PROBLEM USING TWO VARIABLES AND THE SYSTEM OF TWO EQUATIONS. PLEASE DO NOT GIVE ME AN ANSWER THAT SOLVES THIS EQUATION USING ONLY ONE VARIABLE.
Sorry for my all caps ^_^

Let the 10s digit be x and the units digit be y

Equation 1: x+y=14

The VALUE of the number is 10x+y.
If the digits are reversed, the new value is 10y+x
So the value has increased by (10y+x) - (10x+y) = 9y-9x
From the information: 9y-9x=18
After dividing by 9:

Equation 2: y - x = 2

Adding the 2 equations: 2y=16 -> y=8
Instead subtracting: 2x=12 -> x=6

So the number is 68 (Check: 86-68=18)

EDIT: "Bail-out" has completely misinterpreted the question.

13 and 46. Im sorry i use mental math. But n&m+v&b=14. m&n=n&m+18. b&v=v&b+18. 13+18 is 31 46+18=64